If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2r^2-7r=12
We move all terms to the left:
2r^2-7r-(12)=0
a = 2; b = -7; c = -12;
Δ = b2-4ac
Δ = -72-4·2·(-12)
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{145}}{2*2}=\frac{7-\sqrt{145}}{4} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{145}}{2*2}=\frac{7+\sqrt{145}}{4} $
| 3(2r-1)=6r | | 15+☺️10x=105 | | 2r²-7r=12 | | x2=223 | | (2n+3)^=(3n=2)^ | | (2x)(2x)=1 | | (2x+5)(2x-5)(3x+7)=0 | | 4/7=x-3721 | | 18-2(5+3x)=4x | | x–9x=9–7 | | |x|(x+2)^2(x-3)^2=0 | | 4=6-0.5x | | 18x-3=10x-11 | | -5(x+3)+3(3x-4)=3(x-3)+10 | | 3n-9=7n+3 | | x=5(x+7)-4(9+x)+25 | | x/4=2=4 | | 7u+1=1 | | 6s-19=5 | | 16/x=32-16 | | 5z+20=35 | | 3(2x+5)=2x-9 | | 64+2y=98 | | 15x=50-40/10 | | 101/2+5x/6=-30 | | 10-5x/6=20/3 | | 5(7y+15)-2(17y+25)=20 | | b÷5+3=13 | | 5x-80/10=10/20 | | 9x+7=-19 | | 5x-x/5=48 | | n+9=1= |